Function generator in C++

Cross-posted from http://blogs.msdn.com/abhinaba/archive/2005/08/12/450868.aspx

Some of us were just chatting about my previous post about function generators and we wondered about whether it can be done in C++ without using function pointers.... Most of my C++ knowledge has been rusted beyond repair but I thought even though its not possible to do directly, one can overload the ( ) operator to simulate this. So it should be possible to code so that the following is valid

FuncGen(Adder)(p1, p2)

Here the part in red semantically behaves like a function generator returning different functions based on the flag you pass. So here's some code in C++ that does it. Again I want to stress that this is not a function generator in C++, it just simulates something like it so that a statement like FuncGen(Adder)(p1, p2) will actually work....

#include <iostream>
#include <string>
using namespace std;

enum FuncType
{
Adder,
Subtractor,
Multiplicator,
};

class CFunc
{
public:
FuncType m_funcType;
template <typename T>
T operator()(T p1, T p2)
{
if (m_funcType == Adder)
return FuncAdder(p1, p2);
else if (m_funcType == Subtractor)
return FuncSub(p1, p2);
else if (m_funcType == Multiplicator)
return FuncMult(p1, p2);
}

private:
template <typename T>
T FuncAdder(T p1, T p2)
{
return p1 + p2;
}
template <typename T>
T FuncSub(T p1, T p2)
{
return p1 - p2;
}
template <typename T>
T FuncMult(T p1, T p2)
{
return p1 * p2;
}
};

CFunc cfunc;
CFunc& FuncGen(FuncType ftype)
{
cfunc.m_funcType = ftype;
return cfunc;
};

int main(int argc, char* argv[])
{
int p1 = 5, p2 = 1;
cout << FuncGen(Adder)(p1, p2) << endl;
cout << FuncGen(Subtractor)(p1, p2) << endl;
cout << FuncGen(Multiplicator)(p1, p2) << endl;
return 0;
}

Instead of using a global variable like cfunc I could have also created a object on the heap in FuncGen and later deleted it but since I have been coding in C# so long that I felt too lazy to write a delete statement.